c语言将一个数开平方并取倒数,经测试这段代码比(float)(1.0/sqrt(x))快4倍



c语言将一个数开平方并取倒,经测试这段代码比(float)(1.0/sqrt(x))快4倍。

给出最精简的1/sqrt()函数:
float InvSqrt(float x)
{
float xhalf = 0.5f*x;
int i = *(int*)&x; // get bits for floating VALUE
i = 0x5f375a86- (i>>1); // gives initial guess y0
x = *(float*)&i; // convert bits BACK to float
x = x*(1.5f-xhalf*x*x); // Newton step, repeating increases accuracy
return x;
}