cxf jax-rs spring client

参考：http://cxf.apache.org/docs/jax-rs-client-api.html

第一步：

根据WS服务端提供的信息 编写一个Service接口

例如：

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import javax.ws.rs.POST;
import javax.ws.rs.Path;
import com.dotwconnect.us.xsd.getallcountries.Customer;
import com.dotwconnect.us.xsd.getallcountries_response.ResultType;
@Path(“/gateway.dotw”)
public interface CountriesService {

@POST
ResultType getAllCountries(Customer customer);

}
[java] view plaincopy
import javax.ws.rs.POST;
import javax.ws.rs.Path;
import com.dotwconnect.us.xsd.getallcountries.Customer;
import com.dotwconnect.us.xsd.getallcountries_response.ResultType;
@Path(“/gateway.dotw”)
public interface CountriesService {

@POST
ResultType getAllCountries(Customer customer);

}

第二步：

通过JAXRSClientFactory 工厂对象创建Service

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CountriesService cs = JAXRSClientFactory.create(“http://localhost:8888″,
CountriesService.class);

Customer c = new Customer() ; //请求参数

ResultType xxx = cs.getAllCountries(c); //访问WS
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CountriesService cs = JAXRSClientFactory.create(“http://localhost:8888″,
CountriesService.class);

Customer c = new Customer() ; //请求参数

ResultType xxx = cs.getAllCountries(c); //访问WS
注释：

发送出去的XML消息，如果要去掉namespace 信息 ，可以将生成的客户端对象中的package-info对象中的@XmlSchema注解中的 namespace 属性删掉。

 

如果返回过来的xml消息。节点名称与我们类名不符合。

如：返回过来的消息为

<result>…</result>

但是我们生成的类名为 ResultType 。

那么使用JAXb Unmarshaller 的时候，就有问题 。解决办法就是给ResultType加上一个@XmlRootElement(name=”result”)注解

 
在Spring中配置

在项目中加入jaxrs-https.xml文件，内容如下：

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<?xml version=”1.0″ encoding=”UTF-8″?>
<beans xmlns=”http://www.springframework.org/schema/beans”
xmlns:xsi=”http://www.w3.org/2001/XMLSchema-instance” xmlns:p=”http://www.springframework.org/schema/p”
xmlns:aop=”http://www.springframework.org/schema/aop” xmlns:tx=”http://www.springframework.org/schema/tx”
xmlns:context=”http://www.springframework.org/schema/context”
xmlns:jaxrs=”http://cxf.apache.org/jaxrs”
xsi:schemaLocation=”http://www.springframework.org/schema/beans

http://www.springframework.org/schema/beans/spring-beans-3.1.xsd

http://www.springframework.org/schema/tx

http://www.springframework.org/schema/tx/spring-tx-3.1.xsd

http://www.springframework.org/schema/aop

http://www.springframework.org/schema/aop/spring-aop-3.1.xsd

http://www.springframework.org/schema/context

http://www.springframework.org/schema/context/spring-context-3.1.xsd

http://cxf.apache.org/jaxrs http://cxf.apache.org/schemas/jaxrs.xsd”>

<jaxrs:client id=”countriesClient”
serviceClass=”com.zf.service.CountriesService”
address=”http://localhost:8888″
inheritHeaders=”true”>
<jaxrs:headers>
<entry key=”Accept” value=”text/xml” />
</jaxrs:headers>
</jaxrs:client>

</beans>
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<?xml version=”1.0″ encoding=”UTF-8″?>
<beans xmlns=”http://www.springframework.org/schema/beans”
xmlns:xsi=”http://www.w3.org/2001/XMLSchema-instance” xmlns:p=”http://www.springframework.org/schema/p”
xmlns:aop=”http://www.springframework.org/schema/aop” xmlns:tx=”http://www.springframework.org/schema/tx”
xmlns:context=”http://www.springframework.org/schema/context”
xmlns:jaxrs=”http://cxf.apache.org/jaxrs”
xsi:schemaLocation=”http://www.springframework.org/schema/beans

http://www.springframework.org/schema/beans/spring-beans-3.1.xsd

http://www.springframework.org/schema/tx

http://www.springframework.org/schema/tx/spring-tx-3.1.xsd

http://www.springframework.org/schema/aop

http://www.springframework.org/schema/aop/spring-aop-3.1.xsd

http://www.springframework.org/schema/context

http://www.springframework.org/schema/context/spring-context-3.1.xsd

http://cxf.apache.org/jaxrs http://cxf.apache.org/schemas/jaxrs.xsd”>

<jaxrs:client id=”countriesClient”
serviceClass=”com.zf.service.CountriesService”
address=”http://localhost:8888″
inheritHeaders=”true”>
<jaxrs:headers>
<entry key=”Accept” value=”text/xml” />
</jaxrs:headers>
</jaxrs:client>

</beans>

然后就可以通过下面的方式获取服务接口了

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ApplicationContext cxt = new ClassPathXmlApplicationContext(new String[]{“applicationContext.xml”,”jaxrs-https.xml”});

CountriesService countriesService = (CountriesService)cxt.getBean(“countriesClient”);