java扑克洗牌算法设计一副扑克52张牌（没有大小王），模拟洗牌实例源码介绍。纸牌类，代表一张纸牌：

public class Card { 

public CardSuit suit; //花色
public int value; //点数，1代表A，11代表J

public Card(CardSuit suit, int value) {
this.suit = suit;
this.value = value;
}

@Override
public String toString() {
StringBuilder sb = new StringBuilder();
switch(suit) {
case SPADE:
sb.append(“黑桃”);
break;
case HEART:
sb.append(“红桃”);
break;
case DIAMOND:
sb.append(“方片”);
break;
case CLUB:
sb.append(“梅花”);
break;
}

switch(value) {
case 1:
sb.append(‘A’);
break;
case 11:
sb.append(‘J’);
break;
case 12:
sb.append(‘Q’);
break;
case 13:
sb.append(‘K’);
break;
default:
sb.append(value);
}
return sb.toString();
}
}

扑克类，代表一副扑克：

[java] view plaincopy
import java.util.Random;
//纸牌的花色，分别是：黑桃，红心，方片，梅花
enum CardSuit {SPADE, HEART, DIAMOND, CLUB};
//52张牌，没有大小王
public class Cards {

public Cards() {
cards = new Card[52];
int index = 0;
for(CardSuit suit:CardSuit.values()) {
for(int i=1; i<=13; i++)
cards[index++] = new Card(suit, i);
}
}
public void showCards() {
for(Card c:cards) {
System.out.print(c);
System.out.print(” “);
}
System.out.println();
}
//洗牌
public void shuffle() {
Card[] target = new Card[52];
int i = 0, j = 26, index = 0, n;
Random rand = new Random();
//交错式洗牌
while(index<52) {
n = rand.nextInt(3) + 1;
while(n>0&&i<26) {
target[index++] = cards[i++];
n–;
}
n = rand.nextInt(3) + 1;
while(n>0&&j<52) {
target[index++] = cards[j++];
n–;
}
}

//切牌，把下半部分和上半部分互换位置
n = rand.nextInt(10)+20;
for(i=0; i<52; i++) {
cards[i] = target[(n+i)%52];
}
}
private Card[] cards;
}

主函数，测试一下上面的内容：

[java] view plaincopy
public class Main {
/**
* @param args
*/
public static void main(String[] args) {
// TODO Auto-generated method stub
Cards cards = new Cards();
cards.showCards();
cards.shuffle();
cards.shuffle();
cards.shuffle();
cards.shuffle();
cards.shuffle();
cards.showCards();
}
}